How much work must be done to pull the plates apart to where the distance between them is 2.0 mm?

1 Answers

• Aaron Krowne

  1 days ago

  Part 1

  

  Part 2

  

  Є0 Dielectricconstant A- Areaofplate d- Distancebetweenplates V - Voltage D- Diameterofcircularplate Given: d = 1 mm = 1 × 10-3 m D = 7 cm 7 x 10-2 m = V = 160 V For circular plate, Area is calculated by. 2 A = πr2 Ꭰ = π 2 = π 7 x 10 2 -2 2 m The Capacitance of parallel Plate capacitor is given by, C= (8.85 × 10-12 F) 1 × 10-3 m ε0 A d 2 7 × 10-2 2 m 11 F = 3.4 × 10 = 34pF The energy stored in parallel plate Capacitor is given by, = 1 1 U = CV2 2 (3.4 × 10−11F) (160 V)2 = 4.35 × 10-7FV2

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